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Sherilee
01-09-2004, 11:44 PM
3 students buy a packet of cereal for \$6.00. The person realises she has overcharged them by a \$1.00 but as you can't divide a \$1 by 3 she gives them 20c each and pockets the 40c So each student has paid \$1.80 she has 40c thats only \$5.80 Wheres the other 20cents?????????

They paid \$1.80 each 20cents back from their original \$2 3x\$1.80 = \$5.40 + the 40cents she nicked = \$5.80 where is the other 20cents??

Mike
01-09-2004, 11:50 PM
You're looking at it the wrong way around :)

the extra 40c takes it from \$5 to \$5.40, plus the 20c each student got back (60c) takes it to \$6.

Make sense?

They got back 20c each = 60c, plus the 40c she pocketed = \$1... \$6 - \$1 = \$5 that should have been charged.

Mike.

Rob99
01-09-2004, 11:56 PM
What if you look at it this way they paid \$1.80 each and got .20c back and she has .40c.
they paid \$1.80 x 3 = \$5.40
change .20c x 3 = .60c
Total = \$6.00
Where the hell did the .40cents come from?

andrew93
01-09-2004, 11:57 PM
Hi Sherilee

The three students have paid \$1.80 each and the shopkeeper has \$5.40 so there is nothing missing. The shopkeeper has the \$5 purchase price plus the 40c overcharge makes \$5.40, each student has 20c each x 3 = 60c, add the 60c and the \$5.40 and there's your \$6. Alternatively, out of the \$6, the shopkeeper has \$6 - 60c = \$5.40 and each student has 20c x 3 = \$6 again. You can't add the \$5.40 and the 40c - because you have counted the 40c twice (it's in the \$5.40 already) and the 3 refunds of 20c have not been counted.

:D

Mike
01-09-2004, 11:57 PM
> Where the hell did the .40cents come from?

The 40c is the difference between what they paid (\$5.40) and what they should have been charged (\$5.00), so she pocketed the 40c.

Mike.

sam m
02-09-2004, 07:17 AM
each student paid \$2
each student got 20c back
therefore each student paid \$1.80
3 x \$1.80 = \$5.40
The cereal only cost \$5
\$5.40 - \$5 = 40c (which is what the person kept)